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NCERT Solutions for Class 10 Maths – Triangles

2017-08-22T09:30:41+00:00 Categories: CBSE|

Exercise 1

Question 1:

Fill in the blanks

A: All circles are ________ (Similar, Congruent)

Solution: All circles are similar.

B: All squares are ________ (Congruent, similar)

Solution: All squares are similar.

C: All _________ triangles are similar. (Isosceles, equilateral)

Solution: All equilateral triangles are similar.

D: Two polygons having the same number of sides are similar, if

(i) Their corresponding angles are […]

NCERT Solutions for Class 10 Maths – Arithmetic Progressions and Geometric Progression

2017-08-22T09:41:33+00:00 Categories: CBSE|

General Form of an A.P:

Let us consider a series with n number of terms:

a1 + a2 + a3 + a4 + a5 + a6 + a7 ……………………………..  = an

The above series of numbers is said to form an Arithmetic Progression (A.P) if,

a2 – a1 = a3 – a2 = a4 – a3 = …………………………. […]

NCERT Solutions for Class 10 Maths – Quadratic Equations

2017-08-22T09:51:28+00:00 Categories: CBSE|

Polynomials with degree 2 are called quadratic polynomials. When this polynomial is equated to zero, we get a quadratic equation.

Its general form is a2 + bx + c = 0, where a, b and c are real numbers and a ≠ 0.

In many real life situations we deal with quadratic equations.

Suppose, we have to make […]

NCERT Solutions for Class 10 Maths – Pair of Linear Equations in Two Variables

2018-10-19T09:39:27+00:00 Categories: CBSE|

Exercise1 

Question 1:

Astitva tells his daughter, “Seven years ago I was seven times as old as you were then and also three years from now, I shall be three times as old as you will be.”  Represent this situation algebraically and graphically.

Solution:

Let the present age of Astitva be ‘x’.

And, the present age of his daughter be […]

NCERT Solutions for Class 10 Maths – Real Numbers

2017-08-22T09:47:29+00:00 Categories: CBSE|

Chapter-1 : Real Numbers

QUESTION-1

Use Euclid’s division algorithm to find the HCF of:

i)135 and 225

ii)196 and 38220

iii)867 and 225

Solution:

i) We start with the larger number i.e 225

By Euclid’s division algorithm,we have

225=1×135+90

135=1×90+45

90=2

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