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State Board Commerce (XI-XII) - Test Papers

State Board Commerce (XI-XII) - Test Papers

Best Gift for Teacher’s Day

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Are you searching for the best gift for a teacher from students like you and your peers? Well, don’t worry as we will break down the details on the best gifts for Teacher’s day and the best gift for a teacher from students!

First of all, teachers love Favorite books, so why not get some fancy book like a thriller, suspense or comic genre book? This is the best gift for teachers from students.

After that, we have Tote bags which teachers (especially women) love. It can have a message like “My favorite teacher” or “Best teacher.”  It is indeed an excellent and thoughtful gift for teacher’s day and the best gift for a teacher from students.

Oh, how about a Cuppa engraved with the memorable pictures of your teacher and your class! Your teacher would love it! It is the best gift for Teacher’s day and the best gift for a teacher from students.

Then, we have a Pen, which a teacher can use for signatures and other writing purposes, which makes the best gift for teacher’s day.

You could also give your teacher a Photo Album, which a collection of all the precious moments spent in school together. It could include a thank you note, with the signatures of the whole. That is sure to get your teacher’s eyes all swelled up with tears. It is indeed the best gift for teacher’s day and best gift for the teacher from students.

Speaking of thank you notes, how about giving her a Thank you letter, which describes in detail how you loved spending time and learning with your teacher, how he or she had always been like a parent to you and how much you are going to miss your teacher when you graduate from school. Make sure that you don’t exaggerate; keep it honest and simple, and your teacher will cherish it forever. We bet that this would be one of the best gifts for a teacher from students like you, also the best gift for teacher’s day.

You could say thanks to your teacher through a slam book . For all unaware of this term, a slam book works by having the slam bookkeeper, i.e., the teacher, in this case, to pin down a question, which would then be circulated to be answered by all the students. This an enjoyable activity for your teacher and class. They would also have loads of fun, and this would be the best gift for teacher’s day plus the best gift for a teacher from students.

Moving on, a plant such as a flower, or a little buddy herb in a pot is also a very distinct gift, as it represents eco-friendliness and would surely be loved by your teacher, especially if he/she has a thing for greenery. It is also the perfect and best gift for teacher’s day.

You could also contribute to your class to get your teacher a box of chocolates; now who passes up such a delicious treat, especially if he/she is a chocoholic! Your teacher would love it, and it would be the best gift for the teacher from students, and the best gift for teacher’s day!

A bouquet of flowers, a keychain/locket with your teacher’s initials or a desk organizer is also some creative gifts and best gifts for teacher’s day, plus the best gift for a teacher from students.

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Ernest Rutherford

By |Categories: Blog, Parents, Students, Teachers|

Ernest Rutherford, one of the greatest scientists of all time, was born in an Island of New Zealand on August 30, 1871. He was the fourth of 12 youngsters. His dad James had little education while his mother Martha filled in as a teacher.

Ernest Rutherford went to Free State schools through 1886, when he won a grant to go to Nelson Collegiate School, a private school. Another scholarship took Rutherford in 1890 to Canterbury College in Christchurch. On finish of the school’s three-year course, Rutherford got a four-year education in liberal and won a grant for a postgraduate year of concentrate at Canterbury. He finished this toward the finish of 1893, earning an M.A. degree with top positions in some disciplines. He was urged to remain yet one more year in Christchurch to conduct research.

In 1895, as the primary research understudy at the University of Cambridge’s Cavendish Laboratory in London, Rutherford distinguished a less complex and all the more industrially feasible methods for identifying radio waves that had been already settled by German physicist Heinrich Hertz. Rutherford and Thomson examined the impacts of X-beams on the conductivity of gases, bringing about a paper about partitioning atoms into particles.

By 1919 he had made another grand revelation: how to initiate a nuclear reaction in a steady element falsely. Atomic reactions were Rutherford’s fundamental concentration for whatever remains of his profession. Rutherford was granted with many honors before his vocation, including a few privileged degrees and associations, for example, the Institution of Electrical Engineers. In 1914 he was knighted. He passed away in Cambridge on October 19, 1937. His tomb lies in the nave of Westminster Abbey, near Sir Isaac Newton’s and Lord Kelvin’s graves.

While Thomson proceeded to analyze what might later be called an electron, Rutherford investigated particles creating radiations. Concentrating on uranium, Rutherford discovered two emissions and called them alpha and beta. At McGill in 1903, Rutherford and has associate Frederick Soddy presented their hypothesis of radioactivity, which asserted radioactive vitality was transmitted from inside a molecule and that when alpha and beta particles were discharged in the meantime, they caused a compound change crosswise over components. Rutherford was likewise credited with finding the radioactive gas radon while at McGill.

In 1907 Rutherford came back to England, taking up the role as a professor. Upon further experimentation that involved alpha particles, Rutherford made the earth-shattering disclosure that almost the aggregate mass of a molecule is packed in a core. In this manner, he brought forth the atomic model, a revelation that denoted the beginning of nuclear material science and eventually prepared to the creation of the atomic bomb. With the approach of World War I, Rutherford directed his concentration toward antisubmarine research.

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JEE Main 2019 Exam : Application Form, Fees, Exam Date, Eligibility, Correction Process

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JEE Main Application Form 2019

The National Testing Agency (NTA) will conduct JEE Main 2019 twice a year and in online mode only. First JEE Main Exam will be held in January and again in April. Application form of JEE Main 1 2019 January Exam will be released on September 1, 2018. JEE Main 2019 application form will be available in online mode till September 30. Similarly, the Application form of JEE Main 2 2019 April Exam application forms will be available on February 08, 2019.

Since the examination is now being conducted in online mode, the candidates will also have to select their preferred exam dates and slots along with the centers while filling the JEE Main 2019 application form. JEE Main 2019 exam will be conducted in 8 different sittings. Read all about JEE Main 2019 latest updates, Exam dates application process, syllabus, exam pattern –

JEE Main Application Form 2019 Important Dates

January Exam

September 1, 2018 – Release of JEE Main 2019 Registration

September 30, 2018 – Final Date to Fill and Submit the application form

October 1, 2018 – Final date to pay the application fee

April Exam

February 8, 2019 – Release of JEE Main 2019 Registration

March 7, 2019 – Final Date to Fill and Submit the application form

October 1, 2019 – Final date to pay the application fee

Correction Period of Application Form yet to be notified by NTA

JEE Main 2919 Application Form Link – https://jeemain.nic.in/jeemainapp/Root/LoginPage.aspx

JEE Main 2019 Exam Date

JEE Main 2019 will be conducted by NTA in two sessions.

January session, the examination will be conducted from January 6 to 20, 2019.

Another session will be conducted from April 6 to 20

Announcement of result for January Exam will be on 31st January 2019 and for April Exam will be on 30th April 2019

JEE Main 2019 Eligibility Criteria

The eligibility criteria of JEE Main 2019 should be read before registration. Since the application forms of ineligible candidates are rejected by the authorities.

Age Limit

  • The candidates should have been born on or after October 1, 1994
  • For SC/ST/PwD candidates, the date of birth should be on or after October 1, 1989

Qualifying Exam

The candidates should have qualified 12th standard (or equivalent) examination in 2017 or 2018 or must be appearing in 2019.

12th Standard Qualifying Marks

There is no prescribed pass percentage. The candidates should have just qualified their 12th standard examination.

Number of Attempts

The candidates can give exam only 3 times

For admissions into IITs, NITs, IIITs and CFTIs

Candidates should have secured minimum 75% marks (65% for SC/ST category candidates) or should be in the top 20 percentile of their respective boards

JEE Main 2019 Reservation Criteria

Other Backward Classes (OBC) if they belong to Non Creamy Layer (NCL) – 27%

Scheduled Castes (SC) – 15%

Scheduled Tribes (ST) – 7.5%

Persons with Disability (PwD)with 40% or more disability – 3% horizontal

List of Things to Keep Ready before filling JEE Main 2019 Application Form

Before filling the JEE Main application form 2019, there are some things which have to be kept ready by the candidates. Documents such as photograph, signature and more have to be scanned and uploaded by the candidates. The candidates should also make sure that while filling the online application form of JEE Main 2019, they have the stable internet connection. The following items are supposed to be kept ready for the process of filling the application form of JEE Main 2019

Aadhaar Card or Aadhaar Enrollment Number: In case of candidates belonging to Assam, J&K or Meghalaya, they are allowed to upload the scanned images of their passport, voter ID or any valid Govt ID.

Email ID and Mobile Number

Scanned images of photograph, the signature of candidate and guardian as per given specifications.

10th and 12th standard details

Credit/Debit/Net banking details if the fee is paid online

Specifications of Documents to be Uploaded

Documents File Format File Size Dimension
Photograph

Name of the candidate and date of photograph must be mentioned beneath the photo

JPEG 4KB to 40KB 3.5cm x 4.5cm
Signature JPEG 1KB to 30KB 3.5cm x 1.5cm
Signature of Father/Mother/Guardian JPEG 1KB to 30KB 3.5cm x 1.5cm

Steps to Fill JEE Main 2019 Application Form

JEE Main 2019 Steps to fill the application form are listed below:

Authentication through Aadhaar/Identity Card – Details of submitted Aadhaar card is matched with the details stored in UID database.

Filling of Online Application Form – Personal, academic, exam related and contact details have to be submitted by the candidates

Verifying Mobile Number & Email ID – Next, the candidates will have to verify their mobile number and email ID.

Uploading of Scanned Documents – The required documents have to be submitted by the candidates.

Payment of Examination Fees – The fee has to be paid in online or offline mode.

Print out of Acknowledgement Page – Finally, the acknowledgement slip has to be downloaded and printed out by the candidates.

JEE Main 2019 Application Fee:

The application fee will be different as per the categories and mode of examinations.

Application Fee payment will be done through credit/debit card.

Candidates can also pay the fee through e-challan of Syndicate/Canara/ICICI bank.

DD, money order, IPO, etc  will not be accepted

The application fee will be nonrefundable.

JEE Main 2019 Exam Fee (For Examination Centres opted in India)

Paper(s) Appearing General/OBC SC/ST/PWD
JEE Main Paper-1 or JEE Main Paper-2 Rs 500 (Boys)

Rs 250 (Girls)

Rs 250 (Boys)

Rs 250 (Girls)

Both JEE Main Paper-1 and JEE Main Paper-2 Rs 1300 (Boys)

Rs 650 (Girls)

Rs 650 (Boys)

Rs 650 (Girls)

JEE Main 2019 Exam Fee (For Examination Centre opted in Foreign Country)

Paper(s) Appearing General/OBC SC/ST/PWD
JEE Main Paper-1 or JEE Main Paper-2 Rs 2500 (Boys)

Rs 1250 (Girls)

Rs 1250 (Boys)

Rs 1250 (Girls)

Both JEE Main Paper-1 and JEE Main Paper-2 Rs 3800 (Boys)

Rs 1900 (Girls)

Rs 1900 (Boys)

Rs 1900 (Girls)

JEE Main Mock Test 2019

NTA will open student registration for practice centre from September 1 onwards. This registration will help candidates appear in JEE Main 2019 mock test. Using the released mock test, the candidates will be able to prepare well for the upcoming examination. Since the mock test will have the same structure as the JEE Main 2019 examination, the candidates will be familiar with the pattern and analyze their preparation. Time management can also be practised using the mock test.

How to register for Practice Centre?

Candidates can follow the steps given below to register for JEE Main 2019 practice centre:

Step 1 – Personal Details: Since you are logging in from your Google or Facebook account, your name will visible on the screen, by default. Enter date of birth, age, Father’s name and gender. Upload both passport size photo and a photo ID proof.

Step 2 – Contact Details: Provide the email address, mobile number, residential address, city and pin code. Select state and district from the dropdown list.

Step 3 – Academic Details: Here, enter the school or institute last attended or attending. Enter Enrollment Number too.

Step 4 – Exam Details: Select the exam interested in from the dropdown menu and mention the number of attempts taken for that particular exam. Click on submit button.

JEE Main 2019 Exam Pattern

Mode of Examination: NTA will conduct JEE Main in online mode only (Computer Based Test).

Duration of the exam: 03 hours.

JEE Main & Advanced Sample Papers - Robomate+

Type of Questions: Objective Type / MCQ questions.

The medium of Question Papers: The candidates will be given a choice in the medium of the question papers. The medium of examination in all test centers will be in English and Hindi Medium. However, for Centre Cities in Gujarat, Daman & Diu and Dadra and Nagar Haveli, the questions will be available in English, Hindi, and Gujarati.

For Paper 1: For BE/B.Tech

Sections Number of Questions Maximum Marks
Mathematics 30 120
Physics 30 120
Chemistry 30 120

For Paper 2: For B.Arch/B.Plan
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Sections Number of Questions Maximum Marks
Mathematics 30 120
Aptitude Test 50 200
Drawing 02 70

Marking Scheme (Same for paper 1 and 2):

  • For every correct answer, 04 marks will be given.
  • Also, there shall be a negative marking of 01 marks for every incorrect answer.
  • No marks will be deducted or awarded in case if the question is left unanswered.

How do I check the progress of my JEE Main 2019 Application Form?

The authorities will be providing “Application Form Progress” feature for all candidates on the left corner of the application window. Using this feature, the candidates will be able to check their status from the listed stage of the application process:

View Application Form

View Scanned Images

View Payment Status

Steps to Remove Discrepancy in Uploaded Images of JEE Main Application Form 2019

The registered candidates will be provided with a time period within which they will able to edit their uploaded images. The candidates who need to edit their images i.e., discrepancies have been found will be informed via email by the authorities. The given steps have to be followed by the candidates:

The candidates will have to log in using their application number, password and security pin.

Click on “View Scanned Images”

Click on “Edit Uploaded Images”. The uploaded images can then be changed by the candidates.

JEE Main 2019 Application Form Correction Process

A definite amount of time will be allotted by the authorities for correction of the submitted application form of JEE Main 2019. During this time period, the registered candidates will be able to edit most of their submitted information. Payment of fees has to be done to make the corrections. However, there may be some details which will not be open for correction.

Forgot Password in JEE Main Application Form 2019?

Reset the password by answering the security question selected during registration process.

Verification code will be sent to the registered mobile number and reset link will be sent to the email id.

The verification code has to be submitted after which password can be reset.

Forgot JEE Main 2019 Application Number?

Click on “I cannot access my account?”

Following that, click on “I forgot my JEE Main application number” button

The candidates will have to enter details like their name, mother’s name, father’s name, date of birth, state of eligibility and security pin.

After these steps are fulfilled, the application number will be given back to the candidates.

JEE Main 2019 Syllabus

The syllabus for JEE Main 2018 shall be as follows:

Mathematics

  • Sets, Relations, and Functions
  • Complex Numbers and Quadratic Equations
  • Matrices and Determinants
  • Permutations and Combinations
  • Mathematical Inductions
  • Sequences and Series
  • Binomial Theorem and its simple applications
  • Limit, Continuity, and Differentiability
  • Integral Calculus
  • Differential Equation
  • Co-ordination Geometry
  • Three dimension Geometry
  • Vector Algebra
  • Statistics and Probability
  • Trigonometry
  • Mathematical Reasoning

Physics 

  • Physics and Measurement
  • Kinematics
  • Laws of Motion
  • Work, Energy, and Power
  • Rotational Motion
  • Gravitation
  • Properties of Solids and Liquids
  • Thermodynamics
  • Kinetic Theory of Gases
  • Oscillations and Waves
  • Current Electricity
  • Electrostatics
  • Magnetic Effects of Current and Magnetism
  • Electromagnetic Induction and Alternating Current
  • Electromagnetic Waves
  • Optics
  • Dual Nature of Matter and Radiation
  • Atoms and Nuclei
  • Electronic Devices
  • Communication Systems

Chemistry (Physical)

  • Some basic concepts in Chemistry
  • States of Matter
  • Chemical Thermodynamics
  • Solutions
  • Equilibrium
  • Redox Reactions and Electrochemistry
  • Chemical Kinetics
  • Surface Chemistry
  • Atomic Structure
  • Chemical Bonding and Molecular Structure

Chemistry (Inorganic)

  • Classification of Elements and Periodicity in Properties
  • General Principles and processes of isolation of metals
  • Hydrogen
  • s-block elements
  • p-block elements
  • d and f- block elements
  • Coordination Compounds
  • Environmental Chemistry
  • Hydrocarbons

Chemistry (Organic)

  • Purification and characterization of Organic compound
  • Some basic principles of Organic Chemistry
  • Hydrocarbons
  • Organic compounds containing Halogen, Oxygen, Nitrogen
  • Polymers
  • Biomolecules
  • Chemistry in Everyday Life
  • Principles related to practical chemistry

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NCERT Science Solutions For Class 10

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NCERT Science solution for class 10 are provided by Robotmate+. With this the students can have access to NCERT Solutions, anytime and anywhere according to their convenience. In CBSE schools these NCERT textbooks are prescribed for class 10 students. NCERT provides solutions with an easy understanding of concepts in an assembled format.

NCERT solutions for Class 10 Science are in a chapter wise format for those students having trouble with solutions to difficult problems. These books are have proved to be very helpful for students in scoring maximum marks in their examination. To have a better understanding of the concepts, a student can contact Robomate+ Expert Teacher in the Robomate+ app.

Chapter 01 Chemical Reactions And Equations

Chapter 02 Acids Bases And Salts

Chapter 03 Metals And Non-Metals

Chapter 04 Carbon And Its Compounds

Chapter 05 Periodic Classification Of Elements

Chapter 06 Life Processes

Chapter 07 Control And Coordination

Chapter 08 How Do Organisms Reproduce

Chapter 09 Heredity And Evolution- I

Chapter 09 Heredity And Evolution- II

Chapter 10 Light – Reflection And Refraction

Chapter 11 Human Eye

Chapter 12 Electricity

Chapter 13 Magnetic Effect Of Electric Current

Chapter 14 Sources Of Energy

Chapter 15 Our Environment

Chapter 16 Management Of Natural Resources

NCERT Solutions for Class 10 Science Chapter 1 – Chemical Reactions and Equation

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Chapter 1

Chemical Reactions and Equations

Students of class 10 preparing for their board examinations must go through NCERT Solutions for a better understanding of concepts and the process of solving a difficult problem. It will help them give their best performance during board exams.

Chemical Reactions and Equations is intended to help students to get accustomed to how a chemical reaction can be represented as an equation which will help us to understand the reaction effectively. NCERT solutions for class 10 science chapter 1 has been provided below to help you understand the subject more efficiently.

Introduction of Chemical Reactions:

It is a reaction in which two elements or compounds react together producing change in physical state, temperature or precipitate resulting in formation of new compounds. Class 10 science chapter 1 notes covers the following topics

Characteristics of Chemical Reactions

The chemical reactions are characterized by

  • Change in State: When wax is heated it results in formation of water and gas
  • Change in Color: Potassium permanganate is purple in color, when citric acid is added, the solution turns colorless.
  • Evolution of Gas: Reaction between sodium carbonate and dilute hydrochloric acid evolves carbon-dioxide gas.
  • Change in Temperature: Zinc granules when reacted with dilute sulphuric acid it results in release of heat.
  • Formation of precipitate: Sulphuric acid and barium chloride results in formation of barium sulphate

Chemical Equations

The representation of a chemical reaction in the form of symbols and formula is called as chemical equation.

Types of Chemical Equation

The chemical equations can be classified based upon different types of reactions as follows

  • Combination reactions: When two elements or two compounds combine together to form a single chemical it is called as combination reaction.
  • Decomposition reactions: When the chemical reaction results in splitting of compound into two or more chemicals
  • Displacement reactions: The reaction which displaces one chemical with the other less reactive material
  • Double Displacement Reactions: The reaction in which the element exchange the ions and results in formation of two new compounds.
  • Oxidation: Addition of oxygen or removal of hydrogen
  • Reduction: Addition of hydrogen or removal of oxygen

NCERT solutions for class 10 science chapter 1 is explained in simple and easy way to the students to get good hold over the subject.

NCERT solutions for class 10 science chapter 1 Questions:

Q1) Why should a Magnesium ribbon be cleaned before burning in air?

 Solution: If left in unused condition, the uppermost layer of Magnesium metal reacts with the atmospheric oxygen and forms Magnesium Oxide (MgO) layer which is a stable compound which prevents any further reactions with Oxygen. The Magnesium brush should be cleaned before using to remove the layer of MgO which formed on the uppermost layer of the brush. After removing the layer the reaction becomes feasible with the atmospheric oxygen.

NCERT solutions for class 10 science chapter 1 Questions:

Q2) Write a balanced equations for the following chemical reactions.

  1. i) Hydrogen + Chloride —-> Hydrogen chloride
  2. ii) Barium chloride + Aluminium Sulphate —-> Barium sulphate + Aluminum chloride

iii) Sodium + Water —-> Sodium hydroxide + Hydrogen

Solution:

  1. i) H2+Cl2 -> 2HCl
  2. ii) 3BaCl2 + Al2(SO4)3 -> 2AlCl3 + 3BaSO4

iii) 2Na + 2H2O -> 2NaOH + H2

Q3) Write a balanced chemical equation with state symbols for the following reactions

  1. i) Solutions of Barium chloride and Sodium sulfate in water react to give solution of Sodium chloride and insoluble Barium sulfate.
  2. ii) Sodium hydroxide solution in water reacts with hydrochloric acid solution to produce water and Sodium chloride solution.

Solution:

  1. i) BaCl2 + Na2SO4 -> BaSO4 + 2NaCl
  2. ii) NaOH + HCl -> NaCl + H2O

Q4) A solution of a substance ‘X’ is used for whitewashing.

  1. i) Name the substance ‘X’ and write its formula.
  2. ii) Write the reaction of the substance ‘X’ named in (i) above with water.

Solution:

  1. i) The substance ‘X’ which is used in whitewashing is Calcium Oxide or Quick Lime and its formula is CaO.
  2. ii) CaO + H2O -> Ca(OH)2

Q5) Why does the colour of copper sulphate solution change when an iron nail is dipped in it?

Solution:

Iron is more reactive than copper so when an iron nail is dipped in copper sulphate solution, the iron displaces copper from the copper sulphate and the colour of the copper sulphate solution changes. The reaction is :

Fe+CuSO4 −>FeSO4+Cu

NCERT solutions for class 10 science chapter 1 Questions:

Q6) Identify the substances that are oxidized and that are reduced in the following equation.

  1. i) 4Na(s) + O2(g) -> 2Na2O(s)
  2. ii) CuO(s)+H2(g)?Cu(s)+H2O(l)

Solution:

The Sodium (Na) in the first equation is getting oxidized with the addition of Oxygen (O2) and the Copper (Cu) in the second equation is reduced since the addition of Hydrogen (H2).

Exercise:

Q1) Which of the statements about the reaction below are incorrect?

2PbO(s) + C(s) -> 2Pb(s)+CO2(g)

(a) Lead is getting reduced

(b) Carbon Dioxide is getting oxidised

(c) Carbon is getting oxidised

(d) Lead oxide is getting reduced

(i) (a) and (b)

(ii) (a) and (c)

(iii) (a), (b) and (c)

(iv) all

Solution:

(i) (a) and (b)

Explanation: (a) because Oxygen is being removed and (b) because the removed oxygen from Lead is added to the elemental Carbon.

Q2) Fe2O3+2Al -> Al2O3+2Fe

The above reaction is an example of a

  1. Combination reaction.
  2. Double displacement reaction.
  3. Decomposition reaction.
  4. Displacement reaction.

Soln:

  1. Displacement reaction.

Explanation: The Oxygen from the Ferrous oxide is getting displaced to the Aluminium metal to form Aluminium Oxide.

Q3) What happens when dilute hydrochloric acid is added to iron fillings? Tick the correct answer.

  1. Hydrogen gas and Iron chloride are produced.
  2. Chlorine gas and Iron hydroxide are produced.
  3. No reaction takes place.
  4. Iron salt and water are produced.

Solution:

  1. Hydrogen gas and Iron chloride are produced.

Explanation: The Chlorine from the Hydrogen chloride is displaced to the Iron fillings undergoing the following reaction.

2HCl+Fe -> FeCl2+H2

Q4) What is a balanced chemical equation? Why should a chemical equation be balanced?

Solution:

The chemical reaction in which the number of atoms in reactant and product side of a chemical equation are equal is known as balanced chemical equation. The Law Of Conservation of Mass is obeyed when the chemical equation is balanced. There is no defined method for Balancing a chemical equation and it is a result of purely a trial and error attempt.

Q5) Translate the following statements into chemical equations and balance them.

(a) Hydrogen gas combines with nitrogen to form ammonia.

(b) Hydrogen sulphide gas burns in air to give water and sulphur dioxide.

(c) Barium chloride reacts with aluminium sulphate to give Aluminium chloride and a precipitate of barium sulphate.

(d) Potassium metal reacts with water to give potassium hydroxide and Hydrogen gas.

Solution:

(a) Unbalanced: H2+N2→NH3

Balanced: 3H2+N2→2NH3

(b) Unbalanced: H2S+O2→H2O+SO2

Balanced: 2H2S+3O2→2H2O+2SO2

(c)  Unbalanced: BaCl2+Al2(SO4)3→AlCl3+BaSO4

Balanced: 3BaCl2+Al2(SO4)3→2AlCl3+3BaSO4

(d) Unbalanced:K+H2O→KOH+H2

                        Balanced:  2K+2H2O→2KOH+H2

Q6) Balance the following chemical equations.

  1. HNO3+Ca(OH)2→Ca(NO3)2+H2O
  2. NaOH+H2SO4→Na2SO4+H2O
  3. NaCl+AgNO3→AgCl+NaNO3
  4. BaCl2+H2SO4→BaSO4+HCl

Soln:

  1. 2HNO3+2Ca(OH)2→2Ca(NO3)2+2H2O
  2. 6NaOH+3H2SO4→H2SO4+6H2O
  3. NaCl+AgNO3→AgCl+NaNO3
  4. BaCl2+H2SO4→BaSO4+2HCl

Q7) Write the balanced chemical equation for the following reactions.

  1. Calcium hydroxide + Carbon dioxide —-> Calcium carbonate + Water
  2. Zinc + Silver nitrate —-> Zinc nitrate + Silver
  3. Aluminium + Copper chloride —-> Aluminium chloride + Copper
  4. Barium chloride + Potassium sulphate —-> Barium sulphate + Potassium chloride

Solution:

  1. 2Ca(OH)2+2CO2→2CaCO3+2H2O
  2. Zn+2AgNO3→Zn(NO3)2+2Ag
  3. 2Al+3CuCl3→2AlCl3+3Cu
  4. BaCl2+K2SO4→BaSO4+2KCl

Q8) Write a balanced chemical equation for the following and identify the type of reaction of each case

  1. KBr+BaI2→KI+BaBr2
  2. ZnCO3→ZnO+CO2
  3. H2+Cl→HCl
  4. Mg+HCl→MgCl2+H2

Soln:

  1. 2KBr+BaI2→2KI+BaBr2 (Double Displacement Reaction)
  2. ZnCO3→ZnO+CO2 (Decomposition Reaction)
  3. H2+Cl→2HCl  (Combination Reaction)
  4. Mg+2HCl→MgCl2+H2 (Displacement Reaction)

Q9) What is meant by exothermic and endothermic reactions? Give examples.

Solution:

When energy is absorbed from the surrounding in the form of heat it is known as     an endothermic reaction. (Example: Photosynthesis, melting of ice, evaporation). On the contrary when energy is released from the surrounding in the form of heat it is known as an exothermic reaction is one in which energy is released from the system into the surroundings. (Example: Explosions, concrete setting, nuclear fission and fusion).

Q10) Why is respiration considered to be an exothermic reaction?

Solution:

For the continuity of life we require energy. This energy is obtained from the food we eat. Through the process of digestion the food molecules are broken down into simpler molecule like glucose. These substances form carbon dioxide, water and certain amount of energy (Respiration process) after coming in contact with the oxygen present in our body cells. Since the energy is in the form of heat (that maintains our body temperature) the respiration is considered to be an exothermic reaction. The reaction taking place is:

C6H12O6+6O2→6CO2+6H2O+Energy

Q11) Why are decomposition reactions called the opposite of Combination reactions? Write equations for decomposition reactions.

Solution:

The reaction between two or more molecules to form a larger molecule is known as combination reaction whereas the splitting of a larger molecules into two or more smaller molecules is known as decomposition reaction. That essentially explains that the decomposition reaction is the opposite of the combination reaction.

In most of the cases the decomposition reaction is endothermic since heat from the surrounding or induced heat is used to break the bonds of the larger molecule. Few examples of decomposition reactions are:

  • ZnCO3→ZnO+CO2
  • CaCO3+Energy→CaO+CO2
  • 2HgO→2Hg+O2

Q12) Write one equation each for decomposition reactions in which energy is supplied in the form of heat, light or electricity.

Solution:

(a) Thermal decomposition reaction (Thermolysis)

Potassium chlorate decomposes into potassium chloride and oxygen when heated strongly. The preparation of oxygen is done through this reaction.

  2KClO3+Heat→2KCl+3O2

(b) Electrolytic decomposition reaction (Electrolysis)

Decomposition of sodium chloride:  Molten sodium chloride decomposes into sodium and chlorine when electricity is passed through it.

2NaCl→electricity2Na+Cl2

(c) Photodecomposition reaction (Photolysis)

Decomposition of hydrogen peroxide: Hydrogen peroxide decomposes into water and oxygen in the presence of light.

2H2O2→light2H2O+O2

Q13) What is the difference between displacement and double displacement reactions? Write relevant equations for the above.

Solution:

When a more reactive substance displaces a less reactive one from its salt solution it is known as a displacement reaction whereas the reaction where a mutual exchange of ions happens between two compounds is known as double displacement.

Only a single displacement takes place in a displacement reaction and two displacements take place between the molecules in  double displacement reaction.

Example:

Displacement reaction

Mg+2HCl→MgCl2+H2

Double displacement reaction

2KBr+BaI2→2KI+BaBr2

Q14) In the refining of Silver, the recovery of silver from Silver nitrate solution involves displacement reaction by Copper metal. Write down the reaction involved.

Solution:

Cu(s)+2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)

Q15) What do you mean by precipitation reaction? Explain by giving examples.

Solution:

A double displacement reaction takes place in which the ions are exchanged between the compounds when two solutions containing soluble salts are combined. One of such compound formed settles down at the bottom of the container because it is in solid form (that is insoluble). The solid formed is known as the precipitate and the term precipitation reaction is given to the respective reaction. Few examples of precipitation reactions are:

  • CdSO4(aq)+K2S(aq)→CdS(s)+K2SO4(aq)
  • 2NaOH(aq)+MgCl2(aq)→2NaCl(aq)+Mg(OH)2(s)

Q16) Explain the following in terms of gain of oxygen with two examples each.

(a) Oxidation

(b) Reduction

Solution:

(a) When oxygen is added to the element in a chemical reaction, to form its respective oxide it is the element being oxidised.

Example:

4Na(s)+O2(g)→2Na2O(s) H2S+O2→H2O+SO2

(b) When the oxygen is being removed from the compound in a chemical reaction, then it is said to be reduced.

Example:

CuO(s)+H2(g)→Cu(s)+H2O(l) 2HgO→2Hg+O2

Q17) A shiny brown coloured element ‘X’ on heating in air becomes black in colour. Name the element ‘X’ and the black coloured compound formed.

Solution:

Copper metal (Cu) is the shiny brown coloured element. It reacts with the atmospheric oxygen to form copper oxide when the metal is heated in air. Copper Oxide is the black coloured compound is the.

2Cu(s)+O2(g)→2CuO(s)

Q18) Why do we apply paint on iron articles?

Solution:

To prevent the iron articles getting rusted they are painted which is the best way to protect the iron. If the metal is left unpainted, it comes in contact with the atmospheric oxygen and in the presence of moisture it forms Iron (III) oxide i.e rust. By painting the surface it does not come in contact with both the moisture and air which prevents rusting.

Q19) Oil and Fat containing food items are flushed with Nitrogen. Why?

Solution:

The primary purpose of filling nitrogen into the food packets which contains oil and fat items is to prevent rancidity which occurs when the oil or fat reacts with the oxygen letting out an unpleasant smell and taste. To prevent this unpleasant smell nitrogen is filled which creates an unreactive surrounding preventing rancidity. Therefore by flushing Nitrogen, an unreactive surrounding is created thus preventing rancidity.

Q20) Explain the following terms with one example each.

(a) Corrosion

(b) Rancidity

Solution:

(a)When a refined metal is oxidised by the atmospheric oxygen to form a more stable compound like oxides, it is known as corrosion. The metal gradually degrades during the corrosion process. The best example of corrosion where the iron gets converted into iron oxide is the Rusting of iron. Goverments of various countries spend millions of dollars annually to prevent rusting of bridges and other monuments.

(b)Through aerial oxidation of the oil and fat present in the food creates an unpleasant taste and foul smell. When the food is kept inside the refrigerator the rancidity is retarded since the low temperature does not promote the oxidation reaction.

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