Test Papers – ICSE – Class – X
MBA Entrance Quantitative Aptitude, Speed Time Distance, Module 2
Hi, in this session we will understand the concept of Relative Speed. What really is a Relative Speed,
let us understand it by using this example. Let’s say this blue colour train is waiting, it is stationery at
a particular station. There is a red colour train that is trying to cross it, something like this. And let’s
say it takes t seconds to cross the stationery train. Now what would have happened had this train
not been stationery but moving instead. Right, you would realise that there would be two different
situations, one, when the blue train is moving in the same direction as the red train, in this case you
would have realised that the red train would take more than t seconds to cross, right. On the other
hand, had the blue train been travelling in an opposite direction to that of the red train, then the red
train would cross the blue train like a whisker, right, it would take less than t seconds to cross, right.
Now both these situations are practical situations, you would have come across these situations
quite often, right. Now the big question is, why does this happen? It happens because of this
concept of Relative Speed. So when does relative speed come into play. When two or more objects
move together, right, so the Relative Speed is, when two or more objects move together, Speed of
one object in relation to that of the other, right, speed of one in relation of that to the other. So,
let’s take a practical situation, when will two objects move in the same direction, let’s say, think of a
situation in everyday life. Let’s say, police chasing a thief, right, they are in the same direction. Let’s
put some values to understand this better. Let’s say the separation between them is hundred
meters, the police is travelling at 25 meters per second and the thief is running at 5 meters per
second, right. After one second what would happen, the police would have moved further by 25
meters, whereas the thief would have moved further by 5 meters, right. So right now the separation
between them is 80 meters, so do you realise that in one second, they have effectively bridged a gap
of 20 meters, right, they were 100 apart earlier, now it is only 80. They have bridged a gap of 20
meters in one second, and that’s what is Relative Speed. Right, so in the same direction, the Relative
Speed is given by the difference of the two speeds, 25 minus 5 is 20. So, in the same direction the
Relative Speed will be given by the difference of the two speeds. So if the Speed are S1 and S2, the
Relative Speed will be S1 minus S2. How much time would the police take to catch the thief?
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MBA Entrance Quantitative Aptitude, Speed Time Distance, Module 1
Hi, in this session we will be doing the concept of Proportionality of Speed and also Average Speed. What really is speed, well, a vehicle which covers a certain distance in certain amount of time, well, it would have covered this distance in some time, it would have travelled in some speed. So speed is nothing but distance upon time. As you would have seen from the formation, speed and distance would be directly proportionate, which means at a higher speed you are expected to cover longer distance in the same amount of time, right. On the other hand, speed and time as you can see are inversely proportionate, which means to cover the same distance you will take less time at a higher speed. Well, that is the proportionality of speed, time and distance. What that means is, if the speed changes in the ratio a is to b, then the time taken to cover the same distance, since time and speed are inversely proportionate, time taken would be in the ratio b is to a, while the distance covered in the same amount of time, remember distance and speed were directly proportionate, so distance covered would be in the same ratio which is a is to b. Let us now look at some of the conversions. How do you convert speeds from meter per second to kilo meters per hour. So one kilo meter per hour is nothing but 5 by 18 meters per second. Which means if I have to convert any value of speed from kilometre per hour to meters per second, I multiple 5 by 18. One meter per second on the other hand would be 18 by 5 kilo meter per hour. It is the reverse, Any idea what is 1 mile, well 1 mile is 1.6 kilo meters so 1 mile per hour would be nothing but 1.6 kilo meter per hour. Now that is as far as the proportionality of Speed, Time and Distance is concerned. Let’s look at the next topic which is Concept of Average Speed. Now when do we use this concept of average speed. When a vehicle is covering different speeds for different amount of time or different distances at different speeds, for example, when different parts of the journey is covered at different speeds, concept of Average Speed comes into play. So let’s look into this particular train.
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MBA Entrance Quantitative Aptitude, Applications of Ratio and Proportion, Module 1
Hello everyone, today we are going to start with the session called Partnership and
Mixtures. Both of these topics are Applications of Ratio and Proportion.
So, let’s first begin with Partnership and considering A, B and C, starts a business with an
investment of 16 lakhs, 12 lakhs and 20 lakhs respectively and the time period of the
investment is 12 months, 8 months and 6 months respectively. Now at the end of the year
the profits or loss ratio is all dependent on the types of partnership. If it is a case of simple
partnership then we consider only investment ratio as a ratio of profit or loss, that is ratio of
16 is to 12 is to 20 that is 4 is to 3 is to 5. Whereas on the other hand, if it is a case of
compound partnership, we do give importance to time period and hence the ratio of profit
or loss is the ratio of investment into time period, that is 16 into 12 is to 12 into 8 is to 20
into 6, which can be further simplified as 192 is to 96 is to 120, which can be further
simplified as 8 is to 4 is to 5. Now, what is our recommendation? Instead of taking product
and then simplifying, can you first cancel the factors and then multiply. Let’s see how, what I
can do is, I can find common factor from each of these three terms. The first common factor
4 into 4, 4 x 4 = 16, 4 x 3 = 12, 4 x 5= 20 and next is 2 x 6 = 12, 2 x 4 = 8 and 2 x 3 = 6 and
finally I can say, 3 x 2, 3 x 1, 3 x 1, so finally we are left out with the term 4 into 2 = 8 is to 1
into 4 = 4 is to 5 into 1 = 5. So, that’s the ratio of profit or loss that is 8 is to 4 is to 5.
Now, while dealing with the questions of partnerships, you need to remember two points.
The first point is, if nothing is mentioned about the type of partnership then you need to
assume it to be compound partnership. And sometimes, salary is a part of distribution, so
what you need to do is, you need to remove the salary first than distribute the profit. That is,
it says, in case an employee or one of the partners need to be given a salary then first
deduct that from the profit and then divide the profit in the given ratio.
Next is, mixtures. To understand this topic mixtures, what I will do is, I will consider one
example. It says that, a vessel contains milk and water in the ratio 3 is to 5. When 6 litres of
water is added to this solution, the ratio of milk and water becomes 5 is to 9. The question
is, how many litres of the solution was present in the vessel originally? The situation is, let’s
understand.
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MBA Entrance Quantitative Aptitude, Introduction to Ratio Proportion, Module 2
Hello everyone, let’s start with the next session of ratio and proportion, which is Direct and Inverse Variation. The first one is Direct Variation. In direct variation what happens. If I consider X and Y are two parameters, Y increases then X also increases. If Y decreases then X also decreases. This form of relationship is called Direct Relationship. That is in direct variation, one quantity increases, the other also increases proportionately and vice versa. So, I can write it as Y is directly proportional to X. In mathematical form, I can say Y upon X is constant. Let us consider an example of speed, distance and time. You know that Speed is equal to Distance upon Time. If Speed is constant so can I say Distance upon Time is also constant? Yes, so, I can say Distant is directly proportional to Time. Now, let us consider. A constant speed of 50 kms per hour, in order to cover 50 kms distance, I can say the time taken will be 1 hour. If I cover 100 kms distance, then the time taken will be 2 hours. That is if distance is multiplied by 2, then time will also be multiplied 2. If the distance is multiplied by 4, that is to cover 200 kms distance the time taken will be 1 into 4 that is 4 hours and so on. That is, the conclusion is, if distance increases time also increases and this form of relationship is direct relationship. In graphical form I can consider the graph of distance verses time as it is a graph passing through origin describing distance increases time increases. Distance decreases time decreases. Now, in the question, two cases will be given to you, describing the relation as direct, and then I can relate those two cases as Y1 upon X1 is equal to Y2 upon X2. Out of these 4 parameters, 3 parameters will be given in the question and you need to find the 4th parameter. By using this relationship I can find the 4th parameter. The practical example if I consider, if you go to shop and if you buy a shirt which is costing Rs. 1200. Now, if you want to buy 5 shirts you need to pay 6000. Yes, cost of 1 shirt is 1200 rupees, cost of 5 shirts will be 6000. So, the conclusion is as the quantity increases the amount to be paid also increases. So, I can say quantity and amount are in direct relation. That’s about direct variation. Next is inverse variation.
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MBA Entrance Quantitative Aptitude, Introduction to Ratio Proportion, Module 1
Hello friends, today we are going to start with the session called properties of ratio, which
comes under Introduction to Ratio and Proportion. What is ratio? Ratio I can say comparison
of quantities having similar units. For example, if I consider age of A is 12 years and age of B
is 18 years. Can I say the ratio of the age is 12 is to 18. Yes, that is the simplified form is 2:3.
2 and 3 are not actual terms there has to be a multiplying factor. Here the multiplying factor
is 6. That is 6 into 2 and 6 into 3 will give me their actual ages.
Let’s now proceed with one more example. I am considering there is a solution of milk and
water where milk is 24 litres and water is 60 litres. Can I say the ratio of 24 and 60 is 2 and
5? It means what, that the ratio of milk is to water is 2 is to 5 or the ratio water is to milk is 5
is to 2. What is fraction of milk here? Out of 2 plus 5, 7 parts, 2 parts are milk. So, I can say
the fraction of milk is 2 by 7 and the fraction of water is 5 by 7.
Now, let’s proceed. I am considering a situation that is A upon 7 is equal to B upon 5 is equal
to C upon 4. Using this relation, I need to find the relation of A, B and C. To understand this if
I consider, A has 7 parts of pizza, B has 5 parts of pizza and C has 4 parts of pizza. But each
part of A, B, C is equal. Can I say, 1/7th of A, will be equal to 1/5th of B, will be equal to 1/4th
of C, that is A is to B is to C is 7 is to 5 is to 4. To understand this, let us consider the alternate
method. The alternate method is A upon 7 is equal to B upon 5 is equal to C upon 4. So,
during equal relation you can equate them to a constant value let’s say K. So, if I consider A
upon 7 is equal to B upon 5 is equal to C upon 4 is equal to K. So, can I say A is 7K, B is 5K, C
is 4K. And hence again I can say A is to B is to C, is 7 is to 5 is to 4. Let’s consider the case as A
is to B is to C is 1 upon 7 is to 1 upon 5 is to 1 upon 4, again you need to find the ratio of
ABC, but this is also a ratio given to you. This is a fractional form given to you. You need to
convert them into an integral form. To convert them into an integral form.
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HOW TO CRACK MHT CET 2016 ENGINEERING AND MEDICAL ENTRANCE EXAM
To prepare for an exam the students need to focus and understand the requirements to qualify any entrance test. The duty of the students or applicants is to keep a track on the changing criteria’s and syllabus for the entrance exams. It’s not an easy task at all for the students to crack up MHT CET test until they are prepared for it, and sometimes luck favors those who at least know what to study, Robomate+ Test Series is the best to give you a complete detail and guidance.
The question arises how to study and manage to crack the MHT CET 2016 entrance tests for medical and engineering courses along with other health sciences. It is an initiative by the Governmet of Maharashtra . a lot of dedication and input is needed to give your 100% for the preparations. When entrance tests are taken in consideration, it is difficult to make a guess of what is possibility of questions. Short listing the syllabus is also wide in itself, you need to cover every aspect as per the syllabus to be confident enough to crack it.
The very important thing is that one should know their weaknesses and strengths according to their subjects. They should try to work on their weaknesses before polishing the strengths. Practice the weak sections, which you are not confident with. Take some practice or mock tests to test yourself and your strong and weak points.
You need to plan out the working of the preparation by taking some coachings, mock tests and schedule your studying hours accordingly. Make sure you work on the subjects that give you a lot of trouble and clear the doubts by having group discussions and frequent self testing. The very important thing is to know the syllabus well and the pattern of the examination paper accordingly you can practice in time and test the preparation.
Many institutes conduct practice tests to give you hint about where do you stand and how much you need to work on any particular area, they rank you on your performance. You need to know the important chapters, topics . You should be clear with all these basic information that will lead you on an easier path of success.
Do not take too much stress, make a schedule and try to follow it keeping in mind the amount of syllabus and the areas of weakness where you need to give time. But do not waste time at your weak points, try to enhance your strengths too. Practicing hard will give you great results of perseverance and dedication.
