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Test Papers – ICSE – Class – X 2017-04-18T04:54:27+00:00

Test Papers – ICSE – Class – X

Test Papers of ICSE Class - X

MBA Entrance Quantitative Aptitude, Averages, Module 2

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Hi in the session we are going to learn about weighted averages for this let us take an example which you must be familiar with let say there are 3 subjects maths science and languages let’s say you scored 60% in maths 70% in Science and 80% in languages the question is what’s the average percentage marks you scored in these 3 subjects will it be 60 + 70 + 80 divided by 3 the simple average which is nothing but 70% what do you think well that will be true only if all the subjects are out of hundred marks or they are out of equal marks am I right or wrong what if I change the weightages of each subject for example let’s say maths is out of 200 marks science out of 300 and languages out of 500 will the answer still be 70% not really because now I will calculate the individual marks in each subjects for example in maths you would have scored 60% of 200 which is 120 in science you would have scored 70% of 300 which is 210 and in languages you whould have scored 80% of 500 which is 400 the sum total of the marks is 120 + 210 + 400 divide by the over all marks which is 200 + 300 + 500 this is how you will calculate the percentage right and it turns out to be 73% now the question is why isn’t it 70% reason is pretty simple in the earlier case We had assumed that all subjects were equally important because all subject had equal marks with this stand you realise that languages the scores that you scored in this subject must be given more importance because it is out of 500 marks as compared to maths which is only out of 200 marks and hence what we have here is a concept of weighted average so we’ll have to assign some ways to each of these scores for example since their marks are in ratio 2:3:5 will assign the weightages of 2, 3 and 5 respectively to the respective percentages which is 60, 70, 80 which means the average percentage marks will be calculated as 2*60 + 3*70 + 5*80 upon the sum of the weights which is 2 + 3 + 5 and that turns out to be 73% now this concept is what we call the weighted average where in different values are assign different weights depending on their importance let us understand this even better using this example if 3kgs of tea powder costing 10 rupees per kg is mixed with 2kg of tea powder costing 25 rupees per kg what will be the average price of the resulting mixture right now we have two varieties of tea powder

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MBA Entrance Logical Reasoning and Direct Interpretation, Matrix Arrangements, Module 1

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Hello everyone let’s study Matrix arrangement let’s go to Matrix arrangement part 1 so what is matrix arrangement basically the data on different parameters are to mapped with each other so for example let say there are Three Students A B and C and their IV sports tennis Hockey cricket and football B likes to play tennis and C likes to play cricket so in this manner some information will be given about different students who like different sports and probably something else also so we need to make a grid and map student A like the sports and do something else so this is matrix arrangement let’s see an example and see how to solve that question so for example 7 friends B, R, K, M, Y, T and F study in 3 different Schools that is A, C and X. Not more than 3 or less than 2 study in any of the schools. Each one has a favorite fruits among pineapple, Banana, Pear, Mango, Watermelon, Sweet lime and Papaya not necessarily in that order. R studies in school X and likes mango where as Y studies in school A and likes pineapple. None in school C likes the fruit pear. T studies in the same school only Y where as M does not study in school C. M likes papaya where as F like watermelon B does not like sweet lime and only two of them study in school X so if you have observe carefully there are three parameters one is friend second is school and the third is fruit so we have 3 columns let’s see how to solve this question step by step so we have one column for student another for school and the next for fruit now in school there are again two columns tick and cross what does tick means it means if B is going to some school then we will write down under tick column if the students are not going to some school then we will write under cross column and similarly for fruits also the first statement

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MBA Entrance Logical Reasoning and Direct Interpretation, Family and Relationship, Module 2

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Hello once again this session is the second part of family relationship where we are going to cover the questions pertaining to family relationships so let’s start the first question varun is the son of Tarun. Sunitha is the daughter of Anita and Umang’s son while Ramesh is Sunita’s mother in law son. If Umang has only one son Tarun, how is Ramesh related to Varun? now if I consider the first statement Varun is the son of Tarun so the Representation will be like this Varun son of Tarun next is Sunita is the daughter of Anita and Umang’s son can I conclude that Umang’s son is the husband of Anita yes now next is while Ramesh is sunitas mother-in-law son now if you consider Ramesh as husband of Sunita that means you are assuming there is only one son of Sunita’S mother in law but you cannot assume Sunita’s mother in law has only one son there is a possibility that Sunita’s mother in law have more than one son if the statement was while Ramesh is sunita,s mother in law’s only son than I can assume that Ramesh is husband of Sunita but since that is been not here so I can say there are 2 cases let’s consider the first case as Ramesh as husband of Sunita Will continue with this case and then will move on to second case where Ramesh is Sunita’s husband’s brother now if umang has only one son tarun so can I say this place will be occupied by Tarun so Varun will be placed here and finally the relationship will be like this that is Umang’s son Tarun, Tarun’s wife Anita their children Sunita and Varun and Ramesh is husband of Sunitha not the question is how is Ramesh related to Varun so in this

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