A particle moving with constant acceleration, moving with constant acceleration of 4 meters per second square covers 60 meters distance in 8th second of its motion. Find the initial velocity of the particle?
This is totally fine.
Displacement in 8th second will be initial speed plus acceleration by 2, 2 into 8 minus 1. Yes or no? So it is 60 = u 4 by 2, 2 into 8 minus 1. This will come out to be u plus 30, so u is equal to 30 meters per second.
Next, a particle start from rest moves with constant acceleration along a straight line if displacement of particle in t seconds is s1, in next t seconds it is s2, in next t seconds it is s3, and so on. Then find the value of s1 raised to s2 raised to s3, like that. And then find the value of this. Particle starts from 0 initial velocity moves with constant acceleration. The displacement of first t second is s1, and the displacement of the next t seconds is again s1, sorry it is s2, then s3 and so on so we need to find a relation between s1, s2, s3, s4 and so on, done.
