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Std 11, Physics,Integration,Ch-03 Application of Calculus

One example. Let’s write, position of a particle, position of a particle in its linear motion varies with acceleration, position of a particle in its linear motion varies with acceleration according to given function. Find the velocity at x = 2 meter if v = 0 for x = 0 meter per second. Acceleration of particle varies with x and we need to find the velocity when the x coordinate or the position is 2 meters if the initial velocity is zero when the position is x = 0 meter.

I think we have the acceleration function and we need to calculate the velocity. Listen class, stop writing. Step one is identification. Sir, we have an acceleration function and we need to find the velocity, so that it’s for sure that we need to integrate. And when we go for the process of integration, the next step would be to use the acceleration differential definition. Now we have two formulas or two definitions for acceleration differential definition. dv by dt or vdv by dx. Now let me ask you which one is useful here. vdv by dx. Because the variable of function is x, so we are supposed to use vdv by dx. Done. So. 

 

2016-03-08T10:12:48+00:00 Categories: Archive - 2015-16|Tags: , , , |0 Comments
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